Math, asked by pranjul1711, 11 months ago

A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?

Answers

Answered by AditiHegde
19

38,500 cm^3 of the volume of the soup the hospital has to prepare daily to serve 250 patients.

Given,

The diameter of the cylindrical bowl used to feed the patient with soup = 7 cm

The height of the cylindrical bowl filled with the soup = 4 cm

Total number of patients = 250

The volume of the cylinder is given by,

V = π*r^2*h

here, r = d/2 = 7/2 = 3.5 cm

Hence, the volume of soup to be prepared is,

⇒ V = 22/7  × (3.5)^2 × 4

∴ V = 154 cm^3

154 cm^3 is the volume of the soup to be prepared for a single patient.

For a total of 250 patients, the volume of soup to be prepared is,

= 250 × 154

= 38500 cm^3

Answered by nikitasingh79
11

Given :  In a cylindrical bowl of diameter 7 cm and bowl is filled with soup to a height of 4 cm.

Radius of cylindrical bowl (r) = diameter/2 = 7/2 cm  

r  = 3.5 cm

Height , h = 4 cm

Now,

Volume of soup in 1 bowl ,V = πr²h

V = 22/7 × 3.5² × 4

V = 22/7 × 3.5 × 3.5 × 4

V = 22 × 0.5 × 3.5 × 4

V = 22 × 2 × 3.5

V = 22 × 7

V = 154 cm³

Volume of soup in 1 bowl ,V = 154 cm³

Volume of soup in 250 bowls = (250 x 154)  

= 38500 cm³

= 38500/1000

[1 cm³ = 1/1000 litres]

Volume of soup in 1 bowl ,V = 38.5 litres

Hence , hospital has to prepare 38.5 litres of soup daily in order to serve 250 patients.

HOPE THIS ANSWER WILL HELP YOU…..

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