The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm³ of wood has a mass of 0.6 gm.
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The mass of the wooden pipe is 3432 gm.
1 cm3 of wood has mass = 0.6 gm
Density(d) of the wood = 0.6 gm/cm³
Inner radius of the pipe = r1 = 24/2 = 12 cm
Outer radius of the pipe = r2 = 28/2 = 14 cm
Length of the pipe = l = 35 cm
Mass of the pipe = density × (volume of the pipe with outer radius - volume of the pipe with inner radius )
=> 0.6 × (π(r2)² l - π(r1)² l)
=> 0.6 × (22/7 × 35 ((r2)² - (r1)²)
=> 0.6 × ( 110 × (196 - 144))
=> 0.6 × (110 × 52)
=> 3432 gm
The mass of the wooden pipe = 3432 gm
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