A pebble is dropped freely in a well from its top it takes 20sec for the pebble to reach water surface. g=10m/s square and speed of sound 330m/s. Find depth of the water surface. The time when eco is heard after pebble is dropped.
Answers
Answered by
4
Answer:
time = 20 sec
g = 10 m/sec square
u = 0 m/sec square
s = ut + 1/2gt square
s = 0 + 1/2 × 10 ×20 ×20
s= 2000 meter
speed of sound =330 m/sec
time taken = 2000/330. sec
time taken =6.06 sec
time taken to hear eco = 20 +6.06 =26.06
Answered by
1
Time 20s
g is 10 m/s^2
Speed of sound 330 m/s
Initial velocity(u)=0
Using displacement(s)= ut + 1/2gt^2
0(20) + 1/2 (10)(20)^
By solving its
1/2 (500)
=250m
Therefore depth of well is 250 m
Now
Time when echo is heard
=time taken for stone to reach well surface + time taken for echo to come back
=20s + depth of well / speed of sound
=20s + 250 / 330
Which is ALMOST 20.75s
Thank you
g is 10 m/s^2
Speed of sound 330 m/s
Initial velocity(u)=0
Using displacement(s)= ut + 1/2gt^2
0(20) + 1/2 (10)(20)^
By solving its
1/2 (500)
=250m
Therefore depth of well is 250 m
Now
Time when echo is heard
=time taken for stone to reach well surface + time taken for echo to come back
=20s + depth of well / speed of sound
=20s + 250 / 330
Which is ALMOST 20.75s
Thank you
Similar questions