a pendulum bob has a Speed 3 metre per second while passing through its lowest position the length of the pendulum is 0.5 m then its speed when it is an angle of 60 degree with vertical is
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If it makes an angle of 60°with vertical, we need to calculate the speed.
It is given below.mV^2 = mV1^2+2mgh m cross 3^2 = V1^2+2*(0.5-0.5cos 60°)*9.806
= V1^2+4.903
V1 = √9-4.903
V1= 2.0 m/sec
The speed will be 2m/sec
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