Question

A pendulum oscillates 20 times in 2.4seconds. the minimum time taken by Bob of pendulum to reach from one of the extreme positions to mean position is

Answer 1

Answer: 0.06 sec

Step-by-step explanation:

Time period of one oscillation is 2.4 / 20 = 0.12 s

Time period is twice that of the time from extreme to mean position.

So, time taken by Bob of pendulum to reach from one of the extreme positions to mean position is 0.12 / 2 = 0.06 s

Answer 2

Answer:

A pendulum oscillates 20 times in 2.4seconds. the minimum time taken by Bob of pendulum to reach from one of the extreme positions to mean position is = 0.03 Sec

Step-by-step explanation:

Pendulum oscillates 20 times in 2.4 Sec

1 Oscillation = Two Swings = 2.4/20 = 0.12 sec

One extreme position to mean = 1/2 Swing

Time taken for 1/2 swing = (0.12/2)*(1/2)  = 0.03 sec

The minimum time taken by Bob of pendulum to reach from one of the extreme positions to mean position = 0.03 Sec