Question

A perfectly straight portion of a uniform rope has mass M and
tension in the rope is TA and at end B it is TB (B
acts on the rope in between points A and B. The tension in the
A )
(A) TB - TA
(B) (TA + TB)/5
mass M and length L. At end A of the segment, the
ice
s's (B> TA). Neglect effect of gravity and no contact
nsion in the rope at a distance L15 from end Ais
(C) (4TA + TB)/5
(D) (TA-T8)/5​

Answer 1

Answer:

The tension in the string will be T and the portion below the rope will have its own weight Mg then the value of the weight will be balanced by the tension.

T=Mg/L where L is the length of the rope.

Now, the tension at L/5th part of the rope will be T = Mg(L-L/5)/L in which the value of the Ta will be 4Mg/5 and the value of the tension Tb at the other end where the length is  L/5 will be Tb = Mg/5.