Question

A perpendicular force of 50N is acting on a surface generates a pressure of 250 Pa.calculate the area of crossection of the surface on which the pressure is acting.

Answer 1

$\textbf{ Hello Mate! }$

We know that,

Pressure produced = Force applied / Area

Here, pressure produced = 250 Pa

Force applied = 50 N

Hence, 250 Pa = 50 N / Area

Pa = N / m^2

250 N/m^2 = 50 N / A

A = 50 N / 250 N/m^2

A = ( 1 / 5 ) m^2

A = 0.2 m^2

Hence, the area of crossection of the surface on which the pressure is acting on it is 0.2 m^2

Have great future ahead!

Answer 2

♥$<b>Hey mate$ ♥

✨ Here's ur answer

Pressure defined as the force applied perpendicular to the surface of an object per unit of area.

Now pressure=250 units
force=50N

So..

P=F/A

250=50/a

A=50/250

A=1/5

$<u>A=0.2m2</u>$

hope it helpzzzzzzzz

$\red{Thanks!!!}$