Question

A person invites 13 guests to dinner party and arranging 8 of them at one circular table and th eremaining 5 at the other in how many ways can he arrange guests

Answer 1

Answer:

Step-by-step explanation:

We have to arrange 8 guest on 1 round table & remaining 5 on other round table

8 guests can be selected in 13C8 ways. remaining 5 guests can be selected in 5C5 ways.

8 guests can be arranged at circular table in 7! ways.

5 guests can be arranged in 4! ways

So, 13C8*7! ways to arrange 8 guests & 4! to arrange 5 guests

so, final answer is 13C8 * 7!*4!  = 13!/40 ways to arrange 8 guests at 1 circular table & remaining 5 at other.

Note, 13C8 is for selection of 8 guests

7! & 4! for arrangement