Question

a person is holding a bucket by Applying a force of 10N. he Moves a horizontal distance of 5m and then Climbs up a vertical distance of 10m. find the total work Done by him.

Answer 1

Work done= mgh
                 = 10*10
                     =100 joules

Answer 2

Case 1:
force= 10 N
Displacement= 5 m
Work done= FScos(theta)
=10* 5* cos(90)
= 50*0
=0J
Case 2:
Force=10 N
Displacement=10m
Work done=FScos(theta)
= 10*10*cos(180)
=100*-1
=-100
Now, total work done= 0+(-100)
=-100J
So, the total work done by the person = -100 J