Question

A person is known to get a target 3 out of 4 shots and another person is known to hit the target 2 out of 3 shots. Find the probability that the target will be hit when they both try

Answer 1

Hope it will be helpful to you.

Answer 2

Answer:

Probability of target being hit = $\dfrac{11}{12}$

Step-by-step explanation:

As given in question,

Probability that the first person will hit the target, P(A) = $\dfrac{3}{4}$

Probability that the first person can't hit the target, P(A') =1 - $\dfrac{3}{4}$

                                                                                             $=\dfrac{1}{4}$

Probability that the second person will hit the target, P(B) = \dfrac{2}{3}

Probability that the second person can't hit the target, P(B') =1 - $\dfrac{2}{3}$

                                                                                                   $=\dfrac{1}{3}$

Probability that the target can't be hit = P(A') x P(B')

                                                               $=\dfrac{1}{4}\times \dfrac{1}{3}$

                                                               $=\dfrac{1}{12}$

Probability that the target will be hit = 1 - P(A') x P(B')

                                                            =1 - $\dfrac{1}{12}$

                                                            $=\dfrac{11}{12}$

Hence, the required probability will be $\dfrac{11}{12}.$