Question

A person moves from Ato B (a distance of 50m)and returns back to A in 1 minute 40 second. What is the average speed of the person?

Answer 1

s= t\d

s=100\50

s=2mpersecond

Answer 2

{\pink{\mathbb{Hola!!}}}

Average Speed={\frac{Total\: Distance}{Total\:time}}

Distance=50+50

=100 m

time=1 min 40 sec

=1×60+40 sec

=60+40

=100 sec

Average speed ={\frac{100}{100}}

Average speed =1 m/s

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