Question

a person observed the angle of elevation of the top of a tower as 30° he walked 50 m towards the foot of the tower along the level ground and found the angle of elevation of the tower as 60 degree find the height of the tower

Answer 1

30m is the answer for your question

Answer 2

We will assume h be the height of the building.

ΔABC tan 60° = AB/BC

√3 = h/x

x = h/√3

And in the Right Angle ABD,

tan 30° = AB/BD

= 1/√3 = h/ x + 50

= h/√3 + 50 = √3h

h = 25√3m

If there is any confusion please leave a comment below.