A person pushes a toy car initially at rest, towards a child by exerting a constant horizontal force F.? The F is of magnitude 5N through a distance of 1m.how much work is done on car?What is final K.E of car?
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kso u =0 and v=? now we know v²-u²=2as
k.e=1/2mv² now..
v²=u²-2as
now K.E =1/2M(2AS-u²)
K.E= 1/2×0.5×(2×10×1)
K.E=5j
i hope your ans is correct if correct so plz like
plz make it brainlist ans
k.e=1/2mv² now..
v²=u²-2as
now K.E =1/2M(2AS-u²)
K.E= 1/2×0.5×(2×10×1)
K.E=5j
i hope your ans is correct if correct so plz like
plz make it brainlist ans
hammadsadguyoxvkzh:
M=0.5 not 5N.
K.E =0.5*0.5*20=5J
m=0.5 then it will be change so 5/10
now it will correct na
plz like and make as brainlist
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