Question

a train accelerates uniformly from 36 kilometre per hour to 72 km per hour in 20 seconds find the distance travelled?

Answer 1

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s
Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s
Time t = 10 s
Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled S = ut + ½ at2
= 10 x 10 + ½ x 0.5 x 10 x 10 m
= 100 + 25 = 125 m

Answer 2

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