a person rowing at the rate of 5km/hr in still water takes thrice as much as time going in 40km upstream as going 40km downstream.find
the speed of the stream
Answers
Answered by
1634
Speed of the boat in water =.5 km/hr
Let the speed of the stream be x km/hr
So, the speed of the boat upstream will be (5-x) km / hr
So, the speed of the boat downstream is (5+x) k/hr
Time given to cover 40 km upstream = 3(time taken to cover dowmstream)
⇒40/ (5-x) km/hr = 3(5+x)
⇒1/(5-x)=3(5+x)
⇒5+x=15-3x
⇒x+3x=15-5
⇒4x=10
⇒X=10/4
⇒X=5/2
∴x=2.5 km/hr
Answered by
783
Let speed of stream be 's'
Let speed of boat in still water be 'b'
Speed of boat in still water = b = 5 km/h
Let time taken by the boat in going 40km downstream be t1 and time taken by the boat in going 40km upstream be t2.
Time = distance/speed
t1 = 40/(b+s)
t2 = 40/(b-s)
He takes thrice as much as time going in 40km upstream as going 40km downstream.
→t2 = 3t1
→40/(5-s) = 3(40/(5+s))
→1/(5-s) = 3[1/(5+s)]
→5+s = 3(5-s)
→5+s = 15-3s
→ s+3s = 15-5
→ 4s = 10
→ s = 10/4
→ s = 5/2
Therefore, speed of the stream is 5/2 kmph
Let speed of boat in still water be 'b'
Speed of boat in still water = b = 5 km/h
Let time taken by the boat in going 40km downstream be t1 and time taken by the boat in going 40km upstream be t2.
Time = distance/speed
t1 = 40/(b+s)
t2 = 40/(b-s)
He takes thrice as much as time going in 40km upstream as going 40km downstream.
→t2 = 3t1
→40/(5-s) = 3(40/(5+s))
→1/(5-s) = 3[1/(5+s)]
→5+s = 3(5-s)
→5+s = 15-3s
→ s+3s = 15-5
→ 4s = 10
→ s = 10/4
→ s = 5/2
Therefore, speed of the stream is 5/2 kmph
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