A person started his journey in the morning at 11.am he covered 3/8 of the journey and on the same day at 4.30pm he covered 5/6 of the journey..find when time when he started his journey?
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Answer: The person started journey at 6:30 a.m
Step-by-step explanation:
Time between 11 am and 4.30 pm = 5hrs 30min = 5.5hrs
In 5.5 hours he covered 5/6 - 3/8 of total distance
⇒ he covered 11/24 of total distance in 5.5hrs
⇒ 11/24 of total distance = 5.5 hours
⇒3/8 of distance = x hours
By Cross Multiplication ⇒ 5.5*3/8 = (11/24)*x
⇒ x = 9/2 = 4.5 hours
He Covered 3/8 of total distance in 4.5 hours this means that he started his journey 4hrs 30 min before 11 am that is he started is journey at 6:30 a.m
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