Question

A person started his journey in the morning at 11.am he covered 3/8 of the journey and on the same day at 4.30pm he covered 5/6 of the journey..find when time when he started his journey?

Answer 1

Answer: The person started journey at 6:30 a.m

Step-by-step explanation:

Time between 11 am and 4.30 pm = 5hrs 30min = 5.5hrs

In 5.5 hours he covered 5/6 - 3/8 of total distance

⇒ he covered 11/24 of total distance in 5.5hrs

⇒ 11/24 of total distance = 5.5 hours

⇒3/8 of distance = x hours

By Cross Multiplication ⇒ 5.5*3/8 = (11/24)*x

⇒ x = 9/2 = 4.5 hours

He Covered 3/8 of total distance in 4.5 hours this means that he started his journey 4hrs 30 min before 11 am that is he started is journey at 6:30 a.m