Question

A person travelling on a straight line moves with a uniform velocity of 3 m/s for a distance 2m and with a uniform velocity of 4 m/s for the next 3m. The average velocity v is approximately:

Answer 1

Explanation:

Travelling with uniform velocity of 3m/s for a distance of 2m

From 3rd eq.

v²-u²=2as

9-0=2a×2

9/4=a

2.25m/s²= a

Now by first eq.

Time=v-u/a

Time= 3-0/2.25

Time= 300/225

And when uniform velocity 4m/s for a distance of 3m

from 3rd eq.

16-0=2a×3

16/6=a

8/3=a

From 1st eq.

Time= 4-0/8/3

Time= 12/8

Time=3/2

So that The Average Velocity=D1+D2/T1+T2

Velocity= 2+3/300/225+3/2

Velocity=5/600+675/550

Velocity= 550×5/1275

Velocity= 2.15m/s