a person walks along a straight road from his house to a market 2.5 km away with a speed of 5 km per hour and instantly turns back and reaches his house with a speed of 7.5 kilometre per hour the average speed of the person during the time interval 0 to 15 minutes is
Answers
Answered by
0
Answer:
Distance between house and market d=2.5 km
From House to market :
Speed of the person v
1
=5km/hr
∴ Time taken t
1
=
5
2.5
hr =0.5 hr =30 min
From market to house :
Speed of the person v
2
=7.5km/hr
∴ Time taken t
2
=
7.5
2.5
hr =
3
1
hr =20 min
Total distance covered D=2.5+2.5=5 km =5000 m
Total time taken T=30+20=50 min =3000 s
∴ Average speed of the person v
avg
=
3000
5000
=
3
5
m/s
Similar questions