Chemistry, asked by aryanarayan030, 4 days ago

A photon having wavelength equal to 500 nm is used for photolysis of a molecule X₂ having bond energy of 144 kJ/mol. The % of the energy of photon which is converted into the kinetic energy of X atoms is X. The value of X is (to the nearest integer) [bc= 1240 eV 10 nm, 1 eV/molecule = 96 kJ/mol]​

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Answered by adeebhussain278
0

Answer:

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Energy of one mole of photons having wavelength 500 nm is:

Medium

Solution

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Correct option is

A

3.97×10

−19

N

A

Energy of one photon E=

λ

hc

energy of one mole photon=N

A

λ

hc

E=N

A

×

600×10

−9

6.626×10

−34

×3×10

8

E=N

A

×

5

19.878

×10

−19

=N

A

×3.9756×10

−19

E=3.97×10

−19N

A

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