Question

A piece of a soild has a mass of 10g . when it is completely immersed in water , the water level rises by 5 ml . determine the density of the solid ?


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Answer 1

Answer:

TheDensityis2

$AsweknowtheDensity=massvolume As\:we\:know\:the\:Density = \frac{mass}{volume.}AsweknowtheDensity= </p><p>volume.</p><p>mass$

Here mass of substance is 10 gm and volume of water displaced by the substance us 5 ml ( The density of water is 1 gm/cc).

FormulaforDensityis= $Formula\:for\:Density\:is =FormulaforDensityis=</p><p></p><p>Density=massvolumeDensity = \frac{mass}{volume}Density= </p><p>volume</p><p>mass$

$Densityofsubstance=105Density\:of\:substance = \frac{10}{5}Densityofsubstance= </p><p>5</p><p>10$

$HenceDensityofSubstanceis2Hence\:Density\:of\:Substance\:is\:2HenceDensityofSubstanceis2$

Answer 2

Answer:

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$\sf \large{We \: know \: ,density \: of \: a \: solid= \frac{m}{v}( \frac{mass}{volume} )}$

$\sf \large{Now, given :}$

$\sf \large{Mass \: of \: the \: solid = 10g}$

$\sf \large{Volume \: of \: liquid( water) = 5ml}$

$\therefore \: {\underline{\underline {\sf {\large{Density \: of \: the \: solid : }}}}}$

$\sf \large{= > \frac{m}{v} = \frac{10}{5} }$

$\sf = > 2$

Explanation:

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