Question

A piece of copper of mass 1.6 gram is dipped in a measuring cylinder containing water and mark 22 ml . The water rises 234 ml mark find: a) Volume of the copper piece b>density of the cooper

Answer 1

Rise in the volume of water when the piece of copper is dipped in to it = 34 ml − 22 ml

= 12 ml

= 12× 10-3 l

1 l = 10-3 m3 = 12× 10 -6 m3

1) Volume of the copper piece = volume of water

displaced by it = 12× 10 -6 m3

2) density, ρ = massvolumeρ =106×10−3kg12×10−6m3ρ= 8.8 × 103 kg /m