Question

A piece of copper weights 0.635g. how many atoms of copper does it contain?

Answer 1

Answer: $0.06023\times 10^{23}$ atoms

Explanation:-

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{0.635g}{63.5 g/mol}=0.01moles$

Now 1 mole of copper atom contains = $6.023\times 10^{23}$ atoms of copper.

0.01 mole of  copper atom contains = $\frac{6.023\times 10^{23}}{1}\times 0.01=0.06023\times 10^{23}$ atoms

Answer 2

Answer:

826857+76766*576=7664468

Explanation:

*68091453688-5646484468-15616556121516+=5