A piece of cork weighs 25g in air. It floats in water with one-fourth of volume inside water. What is the apparent weight of piece in water ?
ecbelango:
about volume and density ?????
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buoyancy force on cork =weight of water displaced by cork
but we know 1/4th part of cork is immersed .e.g. it displaced volume of water equal 1/4 th of its own volume.
hence, weight of water 1/4th volume of cork would be equal to the weight of the floating cork .
hence
apparent weight=real weight -buoyancy weight (force)
=1/4th weight of cork -1/4th weight of cork=0
but we know 1/4th part of cork is immersed .e.g. it displaced volume of water equal 1/4 th of its own volume.
hence, weight of water 1/4th volume of cork would be equal to the weight of the floating cork .
hence
apparent weight=real weight -buoyancy weight (force)
=1/4th weight of cork -1/4th weight of cork=0
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