Question

A piece of ice is connected to a steam chamber by a metallic rod of length 15cm and diameter 5mm. Find the rate of melting of ice. Coefficient of thermal conductivity of metal is 0.25 CGS unit and latent heat of melting of ice is 80 calg-1 .

Answer 1

Answer:

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calf 1 hahbbb

Answer 2

Given info : A piece of ice is connected to a steam chamber by a metallic rod of length 15cm and diameter 5mm. Coefficient of thermal conductivity of metal is 0.25 CGS unit and latent heat of melting of ice is 80 cal/g.

To find : the rate of melting of ice is ...

solution : energy gained by ice = energy released by steam chamber (heat through metallic chamber )

⇒dm/dt × L = kA ∆T/x

⇒dm/dt = (KA/L) × ∆T/x

here K = thermal conductivity = 0.25 in cgs unit

A = πr² = π(5mm/2)² = 3.14 × (0.25 cm)² = 0.19625 cm²

L = latent heat of ice = 80 cal/g

x = length of metal rod = 15 cm

∆T = temperature change = 100°C - 0°C = 100°C

now, dm/dt = 0.25 × 0.19625/80 × 100/15

= (0.25 × 0.19625 × 100)/(80 × 15)

= 0.004088 g ≈ 0.0041 g

Therefore the rate of melting of ice is 0.0041g/s