Question

A piece of rope is10m long and is cut into three pieces. If the length of two pieces is 5/2 m and 2 1/5 respectivaly. Find the length of the third piece.

Answer 1

Answer:

5.3

Step-by-step explanation:

x+5/2+21/5=10

x+5/2+11/5=10

LCM:

10x+25+22/10=10

10x+47=10×10

10x+47=100

10x=100-47

10x=53

x=53/10

x=5.3

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Answer 2

$\rule{200}3$

$\tt\huge{\red{AnSwEr:-}}$

$\tt\large{\green{GiveN:-}}$

Total length of the rope = 10m

If the rope is cut in 3 pieces

Length of the 1st piece = 5/2m

Length of the 2nd piece = 2 1/5 = 21/5.

$\tt\Large{\green{To\: find:-}}$

Length of the 3rd piece?

$\tt\large{\red{Solution:-}}$

x = total length - (length of 1st piece+length of second piece)

= 10 - (5/2 + 21/5)

= 10 - (25/10 + 42/10)

= 10 - (25 + 42/10)

= 10/1 - 67/10

= (100 - 67)/10

= 33/10

= 3 3/10m

Therefore, the length of remaining piece is 3 3/10 m.

$\rule{200}3$