A piece of stone is dropped from a tower 45m high while falling its uniform accelaration was 10m/s2.How long will it take to touch ground at the moment of touching the ground what would be its velocity?
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by using equation v^2-u^2=2as
u^2=2×10×45=900
u=30
therefore it's velocity is 30
now time=by equation=v=u+at
30=at
now,30=10t
now 30/10=3=t
u^2=2×10×45=900
u=30
therefore it's velocity is 30
now time=by equation=v=u+at
30=at
now,30=10t
now 30/10=3=t
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