Question

a piece of wire is bent in the shape of an equilateral triangle of each side 6.6cm.it is re bant to form a circular ring.what is the diameter of the ring​

Answer 1

Answer:

8.4cm

Step-by-step explanation:

perimeter of the∆ = 4×6.6cm

=26.4cm

P of circle = 2πr

=2×22/7×r = 26.4

=44/7r=26.4

=r=26.4×7/44

=r =4.2cm

so diameter is 4.2 ×2=8.4cm

PLEASE MARK ME BRANIEST

Answer 2

Answer:

perimeter of triangle = circumference of circle

a + b + c. = 2 π r

6.6 +6.6 + 6.6. = 2 × 22/7 × r

19.8. = 2 × 22/7 × r

19.8 × 7 / 2× 22 = r

138.6 / 44. = r

3.15. = r

diameter = 2 × radius

diameter = 2× 3.15

= 6.3 cm

if you want you can also use the formula for circumference of circle as 'πd'.

hope it helps.....

:)