Question

A piece of wire of resistance 20 ohm is drawn out so that its length is increased to twice its original length . calculate the resistance of the wire in the new situation ( class 10)​

Answer 1

Explanation:

As we know that Resistance is directly proportional to the length of the material (such as wire etc.)

so Resistance in new situation = 40 ohm

Solution is above in attachment

Answer 2

Answer:

We know that ,

Resistance is directly proportional to lenght and inversely proportional to area,

R ∝ L / A

So ,

$R1 = \frac{l}{a } = 20Ω$

$R2 = \frac{2l}{\frac{a}{2} }$

$R 2=\frac{4l}{a}$

R 1 = R 2

R 2 = 4 ( l / a )

R 2 = 4 × 20

R 2 = 80 Ω

Hope it helps you!

pls mark brainliest!