Question

A piggy bank contains ₹370 in the notes of dominations of 10 and 50 . If the number of 10 rupee notes is one than that of 50 rupee , find the number of notes of each type .

Answer 1

Given
Total money =370
let
No. of 10rupeenotes=x+1
no. of 50rupee notes=x


value

50rupee notes=50(x)
10rupee notes =10(x+1)
=10x+10

Final. equation
10x+10+50x=370
60x=370-10
60x=360
x=360/60
x=60




Conclusion


number. of 50rupee notes=6
number of 10rupee notes =6+1=7

Answer 2

SOLUTION :

 

Let the number of 50 rupee notes = a

Then the number of 10 rupee note = (a+1)

(as according to the question the number of 10 rupee notes is one than that of 50 rupee)

Value of 50 rupee notes = 50 × a

Value of 10 rupee note = 10(a+1)

Total money = 50 × a + 10(a+1)

                     = 50a + 10a +10

Now,

50a + 10a + 10 = 370

[as the piggy bank contains total money Rs 370]

⇒ 60a + 10 = 370

⇒ 60a = 370 - 10

[transporting 10 to RHS]

⇒ 60a = 360

⇒ a = 360 ÷ 60

⇒ a = 6

Therefore,

Number of 50 rupee note = a = 6

Number of 10 rupee notes = (a+1) = 6+1 = 7

CHECK :

Total money = 50 × 6 + 10 × 7 = 300 + 70 = Rs 370