A pipe of diameter 56 cm is 20 m. long. Find the cost of painting of the surface of this pipe at the rate of rs 15 puer m2
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d = 56cm= 0 .56m
r = 0.28m
h = 20m
CSA = 2 Pi 10th
= 2×(22÷7)×0.28×20
=35.2 sq.m
total cost =35.2 ×15= Rs 528
r = 0.28m
h = 20m
CSA = 2 Pi 10th
= 2×(22÷7)×0.28×20
=35.2 sq.m
total cost =35.2 ×15= Rs 528
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