Question

a plane area of 100 cm square is placed in uniform electric field of hundred Newton per coulomb such that the angle between area vector and electric field is 60 degree determine the electric flux over the surface area

Answer 1

electric flux=EAcosx

=100×100×10^-4×cos60

=1/2=0.5

Answer 2

The electric flux over the surface area is 0.5 Vm.

Explanation:

Given the electric field, E = 100N/C .

The area of the plane, $A=100cm^2=0.01m^2$.

The angle between area vector and electric field,$\theta=60^0$.

The electric flux through surface area is given as

$\phi=EAcos\theta$.

substitute the given values, we get

$\phi=100N/m\times0.01m\timescos60$

$\phi=0.5 Vm$.

Thus, the electric flux over the surface area is 0.5 Vm.

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