Question

A point charge of 100 micro coulumb is placed at (3i+4j). Find the electric field intensity at point (2i+3j).

Answer 1

Charge (q) = 100uC = 10^-4 C

Point Charge = q0

Distance (r) = (3i+4j) - (2i+3j)

r = i + j

r = √(1 + 1) = √2 m

So, electric field, E =>

E = (1/4π€)×q/r^2

E = 9×10^9×10^-4 / √2^2

E = 9 × 10^5 / 2

E = 4.5 × 10^5 N/C....●

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Hope it was helpful.