Physics, asked by abdalla234, 13 days ago

A point charge q=3.2nC experiences a force 8x10-6 N. What is the external electric field strength?

Answers

Answered by jagmohansinghgurjar6
1

as we know that,

E= F×Q

Or we have given that,

q= 3.2nC=3.2×10^-9C

and F= 8×10^-6N

so, E = 3.2×10^-9×8×10^-6= 2.56×10^-14 N/C

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