A point charge q=3.2nC experiences a force 8x10-6 N. What is the external electric field strength?
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as we know that,
E= F×Q
Or we have given that,
q= 3.2nC=3.2×10^-9C
and F= 8×10^-6N
so, E = 3.2×10^-9×8×10^-6= 2.56×10^-14 N/C
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