Question

A point charge 'q' is kept at each of the vertices of an equilateral triangle
having each side 'a'. Total electrostatic potential energy of the system
is:​

Answer 1

Answer:

(1/4π£.)3q/a

Explanation:

Answer 2

Answer:

$E_s=\dfrac{3kq^2}{r}$.

Explanation:

Given :

Three point charges q are kept on the vertices of an equilateral triangle.

Sides of equilateral equilateral triangle is a.

We know , potential energy between two charges is defined as :

$E=\dfrac{kq_1q_2}{r}$

Here , $q_1\ and\ q_2$ are charges and r is distance between them.

In the given question three pairs each having charge q are their :

Potential energy of each pair ,  $E=\dfrac{kq^2}{a}$

Therefore, potential energy of the system , $E_s=3\times\dfrac{kq_1q_2}{r}$

$E_s=\dfrac{3kq^2}{r}$

Hence , this is the required solution.