A point is selected at random from the interior of a circle. the probability that nt the selected point is mid way or is closer to the center than the boundary of the circle is
Answers
Answered by
20
let the radius of the circle be R, then area of it is π R².
Now the area in which the needle will fall such that it's midway or closer to the centre than the boundary will be A CIRCLE OF RADIUS r = R/2.
its area is π r² = π R²/4.
so probability of that event,
P(E) = (favorable region) / (total region)
P(E) = (π R²/4) / (π R²)
so,
P(E) = ¼
hope you got help from my answer if yes then please mark my answer as brainliest ☺️☺️
Now the area in which the needle will fall such that it's midway or closer to the centre than the boundary will be A CIRCLE OF RADIUS r = R/2.
its area is π r² = π R²/4.
so probability of that event,
P(E) = (favorable region) / (total region)
P(E) = (π R²/4) / (π R²)
so,
P(E) = ¼
hope you got help from my answer if yes then please mark my answer as brainliest ☺️☺️
Similar questions