Question

a pole stand erect on the ground if the angle of elevation of the top of the pole from a point 90 m away from the foot of the pole is 30° find the height of the pole

Answer 1

Step-by-step explanation:

$use \: tan(30) = 1 \div \sqrt{3} \ \\ \tan( \alpha ) = h \div b \\ h = b \tan( \alpha ) \\ h = 90tan(30) \\therefore \: h = 90 \sqrt{3}$

Answer 2

Answer:

Suppose AB represents the pole,

O is angle of elevation at the top of the pole  

from a point 60 m away from the pole.

Then, OA = 60 m, ∠O = 30  

o

Step-by-step explanation: