a pool has a uniform circular cross section of radius 5 m and uniform depth 1.4 m . it is filled by a pipe which delivers water at the rate of 20 l L per sec . calculate , in min the time taken to fill the pool . if the pool is emptied in 42min . by another cylindrical pipe through which water flows at the 2 m per sec , calculate the radius of the pipe in cm
Answers
Answered by
14
Radius of pool r = 5m
Height of pool h = 1.4 m
Thus volume of pool = pi r^2 * h
= 22/7 * 25 * 1.4
= 110 m^3
1 m^3 = 1000 lit
So Volume = 110000 Lit
pool filled in 1 sec = 20 lit
in time T = 110000
Thus T = 110000 / 20
T = 55000 Sec
= 55000/ 60
= 916 min
Height of pool h = 1.4 m
Thus volume of pool = pi r^2 * h
= 22/7 * 25 * 1.4
= 110 m^3
1 m^3 = 1000 lit
So Volume = 110000 Lit
pool filled in 1 sec = 20 lit
in time T = 110000
Thus T = 110000 / 20
T = 55000 Sec
= 55000/ 60
= 916 min
Similar questions