Question

A potential difference of 100 V is appliedacross a resistor of resistance 50 ohms for 6 minutes58 seconds. Find the heat produced in(i) joule (ii) calorie.​

Answer 1

Answer :-

(i) Heat produced in 'Joule' = 83600 J

(ii) Heat produced in 'Calorie' = 19980.87 Cal

Explanation :-

We have :-

→ Potential difference (V) = 100 V

→ Resistance (R) = 50 Ω

→ Time (t) = 6 minutes 58 seconds

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Firstly we have to convert the unit of given time, into seconds .

⇒ 1 min = 60 sec

⇒ 6 min 5 sec = (6 × 60) + 58

⇒ (360 + 58) sec

⇒ 418 sec

Heat produced in 'Joules' will be :-

H = V²t/R

⇒ H = [(100)² × 418]/50

⇒ H = [10000 × 418]/50

⇒ H = 4180000/50

⇒ H = 83600 J

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Now, heat produced in 'Calories' will be :-

⇒ 4.184 J = 1 Cal

⇒ 83600 J = (83600/4.184) Cal

⇒ 19980.87 Cal

Answer 2

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GIVEN DATA :

• V= 100 V

( Here V means Volt )

• R = 50Ω

(Here R means Resistance)

• t = 6 minutes and 58 seconds

= (6×60+58)s

=(360+58)s = 418s

( Here t means Time )

• H = ?

(Here H means Heat)

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• H = V² t / R

• = (100 V )² × 418 s / 50Ω

• 100 × 100 × 418/ 50J

• =200× 418 J

• 83600 J

• So power produced in the circuit , P =(V²)/R

i.e. P = 100×100/50

= 200 watt = 200 J/s.

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We know

• Energy

= (200 × 418)J = 83,600J

• Heat generated

• = 83600 Joules

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H = V² t / 4.18 cal

= (100)² × 418 / 4.18 × 50 cal

• = 100 × 100 × 100/50Cal

• 2 × 10 ⁴ cal

Heat produced

= 2 × 10 ⁴ calories

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We know that

Heat produced in 'Calories'

will be :-

• 1 calorie = 4.184J

• So, energy= (83,600)/4.184

= 19,980.87 calories.

energy = 19,980.87 calories

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