Question

A potentiometer wire has length 10m and resistance 10ohm. it is connected to a battery of emf 11 volt and internal resistance 1 ohm

Answer 1

We have,
1) Length of Potentiometer wire, L = 10 m
EMF of Battery, V = 11 V
Internal Resistance of battery, r= 10 ohm
Resistance of wire, R = 10 ohm

2) Equivalent Resistance (series) ,
$R_{eq} = R + r$
$R_{eq} = 10\Omega+ 1\Omega = 11 \Omega$

3) Therefore, By Ohm 's Law,
$V = IR_{eq} \\ => I = 1 A$

Therefore, Current flowing in the Circuit is 1 A.
Hope, you wanted current in above question.

Answer 2

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