A pressure of 1000 Pa, acts on a surface of area 15 cm2 by a block of mass ‘m’. Calculate ‘m’. Calculate the new pressure exerted by the same block if the area ofcontact with the surface becomes 10 cm2.
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Consider acceleration due to gravity as 10m/s2
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Pressure = 1000 Pa
Area = 15 cm² = 0.0015 m²
g = 10 m/s²
Thrust = F = mg
= 10 m
Pressure = Thrust ÷ Area
1000 Pa = 10 m ÷ 0.0015
10 m = 1000 × 0.0015
10 m = 1.5
m = 1.5 ÷ 10
m = 0.15 kg
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∴ mass = 0.15 kg
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Area = 10 cm² = 0.001 m²
Force = mg
= 0.15 × 10
= 1.5 N
New Pressure = Force / Area
= 1.5 ÷ 0.001
= 1500 Pa
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Area = 15 cm² = 0.0015 m²
g = 10 m/s²
Thrust = F = mg
= 10 m
Pressure = Thrust ÷ Area
1000 Pa = 10 m ÷ 0.0015
10 m = 1000 × 0.0015
10 m = 1.5
m = 1.5 ÷ 10
m = 0.15 kg
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∴ mass = 0.15 kg
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Area = 10 cm² = 0.001 m²
Force = mg
= 0.15 × 10
= 1.5 N
New Pressure = Force / Area
= 1.5 ÷ 0.001
= 1500 Pa
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