A printer uses 837 digits to number the pages of a book how many pages are there in the book
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Hey There!
Let's solve this interesting question.
The printer prints 837 digits.
-> There are nine single-digit numbers [1,2,...,9]
Let's remove 9 from 837.
837 - 9 = 828 digits left
-> The two-digit numbers are 10,11,12,...,99.
Thus, there are 90 two-digit numbers
So, they take up 90*2 = 180 digits space.
Let's remove 180 from 828.
828 - 180 = 648
Thus, 648 digits left.
Now, the three digit numbers start: 100,101,102, 103,...
Each such page takes 3 digits of printer ink.
Let number of three-digit pages = n
Then 3n = Number of digits left
So, 3n = 648
So, n = 216
Thus, there are 216 pages with three-digit numbers.
Thus, now we can add the total number of pages:
Number of pages = 9 + 90 + 216 = 315
Thus, The book has 315 pages.
Hope it helps
Purva
Brainly Community
Let's solve this interesting question.
The printer prints 837 digits.
-> There are nine single-digit numbers [1,2,...,9]
Let's remove 9 from 837.
837 - 9 = 828 digits left
-> The two-digit numbers are 10,11,12,...,99.
Thus, there are 90 two-digit numbers
So, they take up 90*2 = 180 digits space.
Let's remove 180 from 828.
828 - 180 = 648
Thus, 648 digits left.
Now, the three digit numbers start: 100,101,102, 103,...
Each such page takes 3 digits of printer ink.
Let number of three-digit pages = n
Then 3n = Number of digits left
So, 3n = 648
So, n = 216
Thus, there are 216 pages with three-digit numbers.
Thus, now we can add the total number of pages:
Number of pages = 9 + 90 + 216 = 315
Thus, The book has 315 pages.
Hope it helps
Purva
Brainly Community
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