Question

A projectile Is fired with velocity u at an angle theta with horizontal. At the highest point of its trajectory it splits up into three segments of masses m , m and 2 m . first part falls vertically downward with zero initial velocity and second part returns via same path to the point of projection. The velocity of third part of mass 2 m just after explosion will be

Answer 1

A shot Is discharged with speed u at an edge theta with level. At the most elevated purpose of its direction it parts up into three sections of masses m, m and 2 m.

Initial segment falls vertically descending with zero starting speed and second part returns through same way to the point of projection.

The speed of third piece of mass 2 m soon after blast will be The speed of 2m would be ucos¤ speed of unreservedly falling is 0 mucos¤= - mucos¤+2mv V=ucos¤.

Answer 2

Answer:

Explanation:

I hope it will help you