a proton, a deuteron and particle are accelerated through the same potential difference and enter in region of uniform electrical field in direction perpendicular to it. the deflection of proton is
Answers
Answer:
Explanation:
Proton Deutron αparticle
mass=m mass=2m mass=4m
charge=q (one proton + one neutron) (two proton+two neutron)
charge=q charge=2q
as radius of path in magnetic field is given by
r=
qB
mϑ
=
qB
2m(KE)
and KE gained by particle
KE=qV
(KE)
proton
=qV ∴r
proton
=
qB
2mqV
(KE)
deuton
=qV ∴r
deuton
=
qB
4mqV
(KE)
α
=2qV ∴r
α
=
2qB
8m∗2qV
∴r
proton
:r
deutron
:r
α
=
2
:
4
:
2
16
=
2
:2:2
=1:
2
:
2