Question

A proton and an alpha particle have the same de broglie wavelength determine the acceleration potential

Answer 1

2 : 1 would be the ratio for accelerating potential .

Charge on alpha particle = 2 q p

Mass of alpha particle = 4 m p

λ a = λ p  

h / 2 m a x q a x v a = h / 2 m p x q p x v p  

m a x q a x v a = m p x q p x v p  

V p / V a = m a x q a / m p x q p  

= 4 m p / m p x 2 q p / q p = 2 : 1