A metallic wire of resistance 20 ohm is stretched until its length is doubled its resistance is it is then cuut into two equal parts these parts are then connected in parallel across 4.0 volt battery fo
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R=v/I
Rp=1/r1+1/r2
Rp=10Ω
10=4/i
I=4/10
i=2/5
I=0.4amp
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