Question

A proton of mass 1.6 x 10-27 kg and
charge 1.6 x 10 19 C. is to be held
motion less between two horizontal
parallel piates 10 cm apart. Find the
voltage required to be applied between
the plates:​

Answer 1

Answer:

A proton is held motionless between two horizontal metal plates 10 cm apart. What voltage should be applied between the plates?

Solution: = 1.67 ∙ 10−27 kg, mass of proton = 1.6 ∙ 10−19 C, charge of proton = 0.1 m The gravitational force on a proton would be balanced by the electric field. Balance of forces

: = v Therefore, v = = 1.67 ∙ 10−27 ∙ 9.8 ∙ 0.1 1.6 ∙ 10−19 ≈ 1 ∙ 10−8 Output: 1 ∙ 10−8