a pump lifts 420 kg of water every minute through vertical height of 30 metre (g=10m/s2) (a)calculate the potential energy gained by the water every minute (b)calculate the useful power of output of the pump
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1) for potential energy = mgh
I.e. 420×10×30 = 126000 J
2) Power= work done/time
i.e. 126000/60
= 2100 W
I.e. 420×10×30 = 126000 J
2) Power= work done/time
i.e. 126000/60
= 2100 W
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