Physics, asked by mitrakuntal, 25 days ago

A pure Round seeded pea plant (RR) is crossed with pure Wrinkled seeded pea

plant (rr). Find the Phenotype & the Phenotypic ratio of F2 generation by

performing Mendelian Monohybrid cross ​

Answers

Answered by nothing19
8

Answer:

3:1’.

Explanation:

A cross between homozygous round seeds plant (RR) and homozygous wrinkled seeds plant (rr) will produce heterozygous (Rr) round seeds plants as F1 generation. The selfing of F

1

will give F

2

generation, where there will be one homozygous dominant round seed plant (RR), two heterozygous round seed plants (Rr) and 1 homozygous recessive wrinkled seed plant (rr). Phenotypically, there will be 3 round seed plants and 1 wrinkled seed plant. Hence, the correct answer is ‘3:1’.

Answered by preethamghagare
0

Answer:

3:1

A cross between homozygous round seeds plant (RR) and homozygous wrinkled seeds plant (rr) will produce heterozygous (Rr) round seeds plants as F1 generation. The selfing of F

1

will give F

2

generation, where there will be one homozygous dominant round seed plant (RR), two heterozygous round seed plants (Rr) and 1 homozygous recessive wrinkled seed plant (rr). Phenotypically, there will be 3 round seed plants and 1 wrinkled seed plant. Hence, the correct answer is ‘3:1

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