A quadratic equation of the form ax^2+bx+ c=0 has positive coefficients ..if alpha and beta are the integral roots of the equation then find the value of alpha square +beta square +alpha.beta
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A quadratic equation of the form ax^2+bx+ c=0 has positive coefficients ..if alpha and beta are the integral roots of the equation ..
so œ+ß=-b/a
→œß=c/a
now œ²+ß²+œß
→(œ+ß)²-2œß+œß
→(-b/a)²-c/a
→b²/a²-c/a
→(b²-ac)/a²
I hope this will help u :)
so œ+ß=-b/a
→œß=c/a
now œ²+ß²+œß
→(œ+ß)²-2œß+œß
→(-b/a)²-c/a
→b²/a²-c/a
→(b²-ac)/a²
I hope this will help u :)
Answered by
1
Hey there! ^_^
Praneeth from Brainly.in here to help!
➺ Given quadratic equation = ax²+bx+ c=0
➺ Roots are α,β
➺ Sum of the roots
=α+β
=-b/a
➺Product of roots
= αβ
=c/a
α²+β²+ αβ
=( α+ β)²-2αβ+ αβ
= ( α+ β)²- αβ
= (-b/a)²-c/a
=b²/a²-c/a
= (b²-ac)/a²
∴There fore, α²+β²+ αβ = (b²-ac) /a²
hope helped!
Praneeth from Brainly.in here to help!
➺ Given quadratic equation = ax²+bx+ c=0
➺ Roots are α,β
➺ Sum of the roots
=α+β
=-b/a
➺Product of roots
= αβ
=c/a
α²+β²+ αβ
=( α+ β)²-2αβ+ αβ
= ( α+ β)²- αβ
= (-b/a)²-c/a
=b²/a²-c/a
= (b²-ac)/a²
∴There fore, α²+β²+ αβ = (b²-ac) /a²
hope helped!
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