Math, asked by kalisipudinandini, 8 months ago

a quadratic polynomial whose zeroes are 1/root 2 qnd 1 is​

Answers

Answered by raushan6198
1

Step-by-step explanation:

given \: that \:  \\  \alpha  =  \frac{1}{ \sqrt{2} }  \\  \beta  = 1 \\ required \: quadratc \: equatin \: is \\  \\  {x}^{2}  - ( \alpha  +  \beta )x +  \alpha  \beta  = 0 \\  =  >  {x}^{2}  -  \frac{1}{ \sqrt{2} } x + 1 = 0

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